3.1214 \(\int \frac {1}{(a-i a x)^{3/4} (a+i a x)^{5/4}} \, dx\)

Optimal. Leaf size=31 \[ \frac {2 i \sqrt [4]{a-i a x}}{a^2 \sqrt [4]{a+i a x}} \]

[Out]

2*I*(a-I*a*x)^(1/4)/a^2/(a+I*a*x)^(1/4)

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Rubi [A]  time = 0.00, antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.040, Rules used = {37} \[ \frac {2 i \sqrt [4]{a-i a x}}{a^2 \sqrt [4]{a+i a x}} \]

Antiderivative was successfully verified.

[In]

Int[1/((a - I*a*x)^(3/4)*(a + I*a*x)^(5/4)),x]

[Out]

((2*I)*(a - I*a*x)^(1/4))/(a^2*(a + I*a*x)^(1/4))

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin {align*} \int \frac {1}{(a-i a x)^{3/4} (a+i a x)^{5/4}} \, dx &=\frac {2 i \sqrt [4]{a-i a x}}{a^2 \sqrt [4]{a+i a x}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 31, normalized size = 1.00 \[ \frac {2 i \sqrt [4]{a-i a x}}{a^2 \sqrt [4]{a+i a x}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/((a - I*a*x)^(3/4)*(a + I*a*x)^(5/4)),x]

[Out]

((2*I)*(a - I*a*x)^(1/4))/(a^2*(a + I*a*x)^(1/4))

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fricas [A]  time = 0.44, size = 31, normalized size = 1.00 \[ \frac {2 \, {\left (i \, a x + a\right )}^{\frac {3}{4}} {\left (-i \, a x + a\right )}^{\frac {1}{4}}}{a^{3} x - i \, a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(3/4)/(a+I*a*x)^(5/4),x, algorithm="fricas")

[Out]

2*(I*a*x + a)^(3/4)*(-I*a*x + a)^(1/4)/(a^3*x - I*a^3)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (i \, a x + a\right )}^{\frac {5}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(3/4)/(a+I*a*x)^(5/4),x, algorithm="giac")

[Out]

integrate(1/((I*a*x + a)^(5/4)*(-I*a*x + a)^(3/4)), x)

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maple [A]  time = 0.04, size = 31, normalized size = 1.00 \[ \frac {2 x +2 i}{\left (-\left (i x -1\right ) a \right )^{\frac {3}{4}} \left (\left (i x +1\right ) a \right )^{\frac {1}{4}} a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-I*a*x+a)^(3/4)/(I*a*x+a)^(5/4),x)

[Out]

2/a/(-(I*x-1)*a)^(3/4)/((I*x+1)*a)^(1/4)*(x+I)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (i \, a x + a\right )}^{\frac {5}{4}} {\left (-i \, a x + a\right )}^{\frac {3}{4}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)^(3/4)/(a+I*a*x)^(5/4),x, algorithm="maxima")

[Out]

integrate(1/((I*a*x + a)^(5/4)*(-I*a*x + a)^(3/4)), x)

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mupad [B]  time = 1.16, size = 27, normalized size = 0.87 \[ \frac {{\left (-a\,\left (-1+x\,1{}\mathrm {i}\right )\right )}^{1/4}\,2{}\mathrm {i}}{a^2\,{\left (a\,\left (1+x\,1{}\mathrm {i}\right )\right )}^{1/4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a - a*x*1i)^(3/4)*(a + a*x*1i)^(5/4)),x)

[Out]

((-a*(x*1i - 1))^(1/4)*2i)/(a^2*(a*(x*1i + 1))^(1/4))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (i a \left (x - i\right )\right )^{\frac {5}{4}} \left (- i a \left (x + i\right )\right )^{\frac {3}{4}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a-I*a*x)**(3/4)/(a+I*a*x)**(5/4),x)

[Out]

Integral(1/((I*a*(x - I))**(5/4)*(-I*a*(x + I))**(3/4)), x)

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